Quiz 5*
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1-6. Use these terms: (C) kcat;   (E) [Et];   (H) kcat/KM ;   (K) KM ;    (S) [S];    (V) v0 ;    (X) Vmax .
Use each answer only once.

         the turnover number

         = [S] when v0 = 0.5 Vmax

          x axis for a Michaelis-Menton graph

         the specificity constant

          = [ES] in the steady state approximation

        has units of M s-1

7-9. Use these terms: (A) α; (B) α′; (C) competitive inhibitor; (M) mixed inhibitor;
(U) uncompetitive inhibitor. Use each answer only once .

        binds both E and ES

         resembles the substrate

          modifies [S] in the Michaelis-Menton equation for a mixed inhibitor

10. Fill in the blank with the appropriate term:                        = [E] [I] / [E I].

1-6. Use these terms: (C) kcat;   (E) [Et];    (H) kcat/KM ;   (K) KM ;    (S) [S];    (V) v0 ;    (X) Vmax .
Use each answer only once.

         an overall rate constant

         the rate when the enzyme is saturated

         has units of s-1

         y axis for a Michaelis-Menton graph

          has units of M

         = 107 – 1010 for extremely efficient enzymes

7-9. Use these terms: (A) α ; (B) α′; (C) competitive inhibitor; (M) mixed inhibitor;
(U) uncompetitive inhibitor. Use each answer only once .

          = 1 + [I]/KI

         binds E but not ES

         binds the enzyme, but not in the active site

10. Fill in the blanks with the appropriate terms: KI′ =       /                        .

1-6. Use these terms: (C) kcat;   (E) [Et];   (H) kcat/KM ; (K) KM ;    (S) [S];    (V) v0 ;      (X) Vmax .
Use each answer only once.

         = [S] when v0 = 0.5 Vmax

          the denominator for kcat

         the turnover number

         the rate of the reaction in the first minute

         has units of M-1 s-1

        in the numerator of the Michaelis-Menton equation

7-9. Use these terms: (A) α; (B) α′; (C) competitive inhibitor; (M) mixed inhibitor;
(U) uncompetitive inhibitor. Use each answer only once .

         binds in the active site

         modifies KM in the Michaelis-Menton
              equation for a competitive inhibitor

         causes Vmax to decrease, which changes KM

10. Fill in the blank with the appropriate term(s): KI′ =                / [ESI].

1-6. Use these terms: (C) kcat;   (E) [Et];   (H) kcat/KM ;   (K) KM ;    (S) [S];    (V) v0 ;    (X) Vmax .
Use each answer only once.

         the numerator for kcat

         the rate of the reaction in the first minute

         has units of s-1

         often indicates an enzyme's affinity for substrate

         shows enzyme efficiency at
               low and high [S]

       in the denominator of the Michaelis-Menton
               equation

7-9. Use these terms: (A) α; (B) α′; (C) competitive inhibitor; (M) mixed inhibitor;
(U) uncompetitive inhibitor. Use each answer only once .

         = 1 + [I]/KI

         binds ES but not E

         causes KM to increase, but Vmax is unchanged

10. Fill in the blanks with the appropriate terms: KI =              /              .

*For complicated reasons that don't change the quiz value, I only printed half of these quizzes.

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