Exam 3 Key Fall 2007 |
|
Multiple Choice Answers:
| 1. C | 6. C | 11. C | 16. C, T |
| 2. C | 7. C | 12. B | 17. B, M |
| 3. A | 8. D | 13. C | 18. B |
| 4. B | 9. C | 14. A, N | 19. D |
| 5. B | 10. C | 15. D, U or R | 20. B |
21. Cytosolic [Ca2+] is normally less than 1 µM. SR (sarcoplasmic reticulum) [Ca2+] is normally 300 µM, although under some conditions it increases. Assume the membrane potential for the SR membrane is ΔV = − 0.040 V (SR → cytosol). ΔGT = R T ln (C2/C1) + Z F ΔV
a. Calculate ΔGT for moving Ca2+ into the SR using the Ca2+ ATPase, which moves 2 Ca2+
for each cycle.
b. Based upon your answer to part (a), how many Ca2+ can be moved into the
organelle per mole ATP hydrolyzed by the Ca2+ ATPase?
c. What happens to both of your answers when SR [Ca2+] is doubled? And what effect
might this change in concentration have on ΔV?
a. ΔGT = (8.314 J/mol-K) (298 K) ln ( 300/1 ) + (+4 ) (96480 J/V-mol) (+ 0.040V)
= (2477.572 J/mol) (5.70) + 15435.8 J/mol) = 14132 J/mol + 15436 J/mol
= 29568 J/mol = + 29.6 kJ/mol
I expected you to recognize that moving Ca2+ from the cytosol into the SR is
unfavorable, both in terms of charge and in terms of concentration.
b. − 30.5 kJ/mol + 29.6 kJ/mol = − 0.9 kJ/mol, so 1 ATP provides enough energy to move
2 Ca2+ only
c. ΔGT = R T ln (600/1) + 15436 J/mol = (2477.6 J/mol) (6.40) + 15436 J/mol
= 31.3 kJ/mol
This doesn't make a huge difference, but it does mean that it's no longer possible to
move 2 Ca2+ with 1 ATP.
22. a. Leucine rotates out of the channel when 2 ACh bind the receptor.
b and c. Answers could vary. Most people had no trouble with this, and when they did, it was usually the result of answering based on what they had learned in physiology or trying to answer for a G protein receptor rather than the ACh receptor.
23. a. 1/2 O2 + 2 H+ + 2 cyt c (Fe2+) → H2O + 2 cyt c (Fe3+)
b. ΔE°′ = 0.816 V − 0.254 V = 0.562 V Reduction potential is an intrinsic property
and does not change with number.
ΔG°′ = − (2) (96480 J/V-mol) (0.562 V) = − 108444 J/mol = − 108.4 kJ/mol
c. − 108.4 kJ/mol /reaction ÷ ( 30.5 kJ/mol/ATP) = ~ 3.6 ATP/reaction
24. Glycolysis and gluconeogenesis use many of the same enzymes, but irreversible reactions require different enzymes. Use the table for parts a and b.
Please read the questions carefully and answer only what is asked.
a. Name two enzymes that catalyze irreversible reactions in glycolysis.
b. Name the enzymes that catalyze reactions in gluconeogenesis that reverse the
glycolysis enzymes you listed in a. If two enzymes are required, you must list both.
c. For each of the reactions you listed, what is the energy gain or loss?
a. glycolysis enzymes |
hexokinase |
PFK-1 |
pyruvate kinase |
b. gluconeogenesis enzymes |
glucose-6-phosphatase |
FBPase-1 |
pyruvate carboxylase + PEP carboxykinase |
c. glycolysis energy change |
cost 1 ATP |
cost 1 ATP |
gain 1 ATP/reaction |
c. gluconeogenesis energy change |
0 |
0 |
cost 1 ATP + cost 1 GTP |
d. Glycolysis produces energy, and gluconeogenesis requires energy.